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| 1. |
Active mass of 5.6 lit N_2 at STP |
| Answer» <html><body><p>22.4M<br/> 0.25M<br/>`1/(22.4)M`<br/> 4M</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/active-367234" style="font-weight:bold;" target="_blank" title="Click to know more about ACTIVE">ACTIVE</a> mass = `(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>//"(<a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a>)")=((5.6)/(22.4))/(5.6)=(1)/(22.4)M`</body></html> | |