AD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed.Prove that Area (∆ADE) : Area (∆ABC) = 3 : 4.

AD is an altitude of an equilateral triangle ABC. On AD as base, anoth

1.	AD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed.Prove that Area (∆ADE) : Area (∆ABC) = 3 : 4.
Answer» AD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed. Prove that Area (∆ADE) : Area (∆ABC) = 3 : 4.

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AD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed.Prove that Area (∆ADE) : Area (∆ABC) = 3 : 4.

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