Add the following rational numbers:(i) \(\frac{-5}{7}\; and\; \frac{3

1.	Add the following rational numbers:(i) \(\frac{-5}{7}\; and\; \frac{3}{7}\)(ii) \(\frac{-15}{4} \;and\;\frac{7}{4}\)(iii) \(\frac{-8}{11}\;and\;\frac{-4}{11}\)(iv) \(\frac{6}{13}\;and\;\frac{-9}{13}\)
Answer» All denominators are in positive numbers. We add it i) \(\frac{-5}{7} +\frac{3}{7}=\frac{(-5 + 3)}{7}=\frac{2}{7}\) ii) \(\frac{-15}{4} + \frac{7}{4}=\frac{(-15+7)}{4}=\frac{-8}{4}\) \(\frac{-8}{4}=-2\) (Dividing by 4 we get) iii) \(\frac{-8}{11}+\frac{-4}{11}= \frac{-8+(-4)}{11}=\frac{-12}{11}\) iv) \(\frac{6}{13} +\frac{-9}{13}= \frac{6+(-9)}{13}=\frac{-3}{13}\)

Add the following rational numbers:(i) \(\frac{-5}{7}\; and\; \frac{3}{7}\)(ii) \(\frac{-15}{4} \;and\;\frac{7}{4}\)(iii) \(\frac{-8}{11}\;and\;\frac{-4}{11}\)(iv) \(\frac{6}{13}\;and\;\frac{-9}{13}\)

Answer»

All denominators are in positive numbers. We add it

i) \(\frac{-5}{7} +\frac{3}{7}=\frac{(-5 + 3)}{7}=\frac{2}{7}\)

ii) \(\frac{-15}{4} + \frac{7}{4}=\frac{(-15+7)}{4}=\frac{-8}{4}\)

\(\frac{-8}{4}=-2\) (Dividing by 4 we get)

iii) \(\frac{-8}{11}+\frac{-4}{11}= \frac{-8+(-4)}{11}=\frac{-12}{11}\)

iv) \(\frac{6}{13} +\frac{-9}{13}= \frac{6+(-9)}{13}=\frac{-3}{13}\)