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Adding sodium amide (NaNH2) to 1-butyne (CH3CH2C CH) would produce: (A) CH3CH2C CNa + NH3 (B) CH3CH2C C-C CH2CH3 + NaH + NH3 (C) CH3CH2C CNH2 + NaH (D) NaCH2CH2C CH + NH3 (E) CH3CH(Na)C CH + NH3 |
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Answer» (A) CH3CH2C CNa + NH3 |
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