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Address of the block is –(a) 2^14(b) 2^16(c) 2^8(d) 2^24The question was asked in my homework.My question is taken from Classful Addressing topic in chapter Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

Answer»

Correct ANSWER is (b) 2^16

The best I can EXPLAIN: Since 180 is between 128 and 191, it is CLASS B ADDRESS n=16.

N = 2^(32-n) = 2^16 = 65,536.



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