After 3 years a principal amount becomes Rs. 3600 and after 6 years th

1.	After 3 years a principal amount becomes Rs. 3600 and after 6 years the amount obtained is Rs. 4800 both at same rate of compound interest. What is the principal amount?1. Rs. 33002. Rs. 21003. Rs. 36004. Rs. 2700
Answer» Correct Answer - Option 4 : Rs. 2700 Given: A₁ = Rs. 3600, N₁ = 3 years A₂ = Rs. 4800, N₂ = 6 years Formula used: A = P × {1 + (R/ 100)}^N Where P = Principal amount, R = Rate of interest in %, N = Number of years Calculation: Assuming Rate of compound interest = R% and principal amount = Rs. X Now, according to equation ⇒ 3600 = X × {1 + (R / 100)}³ ----(1) ⇒ 4800 = X × (1 + (R / 100))⁶ ----(2) Dividing Equation 2 by Equation 1 ⇒ 4800/3600 = {1 + (R / 100)}³ ⇒ 4 / 3 = {1 + (R / 100)}³ ----(3) Substituting Equation (3) in Equation (1) ⇒ 3600 = X × (4 / 3) ⇒ 3600 × (3 / 4) = X ⇒ 2700 = X ∴ Principal amount is Rs.. 2700.

After 3 years a principal amount becomes Rs. 3600 and after 6 years the amount obtained is Rs. 4800 both at same rate of compound interest. What is the principal amount?1. Rs. 33002. Rs. 21003. Rs. 36004. Rs. 2700

Answer» Correct Answer - Option 4 : Rs. 2700

Given:

A₁ = Rs. 3600, N₁ = 3 years

A₂ = Rs. 4800, N₂ = 6 years

Formula used:

A = P × {1 + (R/ 100)}^N

Where P = Principal amount, R = Rate of interest in %, N = Number of years

Calculation:

Assuming Rate of compound interest = R% and principal amount = Rs. X

Now, according to equation

⇒ 3600 = X × {1 + (R / 100)}³ ----(1)

⇒ 4800 = X × (1 + (R / 100))⁶ ----(2)

Dividing Equation 2 by Equation 1

⇒ 4800/3600 = {1 + (R / 100)}³

⇒ 4 / 3 = {1 + (R / 100)}³ ----(3)

Substituting Equation (3) in Equation (1)

⇒ 3600 = X × (4 / 3)

⇒ 3600 × (3 / 4) = X

⇒ 2700 = X

∴ Principal amount is Rs.. 2700.

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