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After calling a wall of `3 m` heigh a mass of weight W drops himself to the ground. If his body comes to a complete stop in `0.15 s`. After his feet touch the ground, calculate the average impulsive force in the vertical direction exerted by ground on his feet.A. `5W`B. `5.21W`C. `3W`D. `6W` |
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Answer» Correct Answer - B Velcoity before strike `u = sqrt(2gh)` Impulse `F Deltat = m(v - u)` `rArr F = (m(v - u))/(t) = (w (0 - sqrt(2gh)))/(g xx 0.15) = 5.21 W` |
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