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After falling from rest through a height `h`, a body of mass `m` begins to raise a body of mass `M (M gt m)` connected to it through a pulley. Find the fraction of kinetic energy lost when the body of mass `M` is jerked into motionA. `M/(M+m)`B. `M/(M-m)`C. `(2M)/(M+m)`D. `M/(2(M+m))` |
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Answer» Correct Answer - A Fraction of `KE` lost`=(1/2"mu"^(2)-1/2(M+m)v^(2))/(1/2"mu"^2)` `=1-(M+m)/m (v/u)^(2)=1-(M+m)/m(m/(M+m))^(2)=m/(M+m)` |
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