1.

(Ag=107.8u, N=14u, O=16u, Na=23u, Cl=35.5u)

Answer»

Moles of AgNo3= 50x 16.9/100x169.8
                           = 0.05mole
Moles of NaCl = 50x5.8/100x58.5
                       =0.05mole
AgNo3 + NaCl ----> AgCl + NaNo3
mass of AgCl = mole x molar mass
                       =0.05 x 143.5
                       = 7.16 g



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