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`Ag_(2)S +NaCN rarr (a)` (a) `+Zn rarr (d)` (b) is a metal. Hence `(a)` and `(b)` areA. `Na_(2)[Zn(CN)_(4)],Zn`B. `Na[Ag(CN)_(2)],Ag`C. `Na_(2)[Ag(CN)_(4),Ag`D. `Na_(3)[Ag(CN)_(4)],Ag` |
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Answer» Correct Answer - B `Ag_(2)S + 4NaCN rarr underset((A))(2Na[Ag(CN)_(2)]) + Na_(2) S` `Na[Ag(CN)_(2)] + Zn rarr Na[Zn(CN)_(2)] + Ag`. |
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