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`Ag^(aq) + e^(-) rightarrow Ag(s)` `[email protected]) = 0.80 V` `Mg^(2+)(aq) + 2e^(-) rightarrow Mg(s)` `E^(@) = -2.73 V` Use the equations above to calcualte the value or `DeltaG^(@0` (in kJ/mol) for the reaction: `Mg(s) + 2Ag^(+)(aq) rightarrow Mg^(2+)(aq) + 2Ag(s)`A. 681B. 341C. `-341`D. `-681` |
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Answer» Correct Answer - D |
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