1.

‘g uls puy s ZE =gQuel+Qo93s JI

Answer»

secΘ +tanΘ = 2/3

1/cosΘ + sinΘ/cosΘ = 2/3

sinΘ + 1 = 2/3 cosΘ

sinΘ = 2/3 cosΘ – 1

Θ = -0.39479 ± 1.176n

Or Θ = -22.6198 degrees, which is in Quadrant 4



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