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Ag107 and Ag109 Average atomic mass=108.5. Find % by mole of each isotope |
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Answer» No bro chemistry is too intresting if one can learn it with such intrest Let Ag107 and Ag109 available in x% and y% respectively. So,x + y = 100 .........(i)Now,(x × 107/100)+(y × 109/100) =108.51.07x +1.09y=108.5 ..........(ii)On multiplying (i) by 1.09 and subtracting (ii) from (i),we get0.02x = 0.5 ==> x = 25On putting x = 25 in (i), we gety = 75Percent of Ag107 =25%Percent of Ag109 =75% Hmmm wo tho hai hi Chemistry is too boring subj... |
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