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AgCl dissolves in `NH_(4)OH` due to the formation ofA. `[Ag(NH_(4))_(2)]Cl`B. `[Ag(NH_(4))_(3)]Cl`C. `[Ag(NH_(3))_(2)]Cl`D. `[Ag(NH_(3))_(2)]OH.` |
Answer» Correct Answer - C `underset("White ppt.")(AgCl(s)) + 2NH_(4)OH (aq)rarrunderset("Soluble complex")([Ag(NH_(3))_(2)]Cl (aq)) + 2H_(2)O(l)` |
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