Aglass tube scaled at both end is 1 m long. It lies horizontally with middle 10cm containing Hg. The two ends of the tube, eqaul in length, contain air at 27^(@)C Neglect the chang in length of Hg column. Then the change in length on two sides is

Aglass tube scaled at both end is 1 m long. It lies horizontally with

1.	Aglass tube scaled at both end is 1 m long. It lies horizontally with middle 10cm containing Hg. The two ends of the tube, eqaul in length, contain air at 27^(@)C Neglect the chang in length of Hg column. Then the change in length on two sides is
Answer» 12.3 cm 10.311 cm 9.9cm 8.49cm Solution :Initially `l= 45CM (2l+10=100cm)` `P_(1)=P_(2)=P(say)` Applying gas law at end A, `(45Ap)/(300)=(45-x)AP_(1)/(273)`.....(II) At end `B(45AP)/(300)=(45+X)AP_(2)/(400)`......(iii) From(i),(ii)and(iii) `(45-X)/(273)=(45+X)/(400) rArr = X=8.49`