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Air flows over the top of an aeroplane wing of area A with speed v_1and past the under side of the wing of area A with speed v_2 Show that the magnitude of the upward in force on the wing L is L =(1)/(2)rho A ( v_1^(2) - v_2^(2)) where rhois the density of the alr. |
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Answer» Solution :Bernouli.s equations `P + (1)/(2)RHO v^(2)+rho gh = a ` CONSTANT The pressure difference ACROSS the upper and lower SURFACE is` Deltap= p_2 -P_1` ` P_1 +(1)/(2)rho v_1^(2)= P_2 +(1)/(2) rho v_2^(2)` because `rhogh`is a constane ` Delta P = P_2 - P_1 = (1)/(2)rho ( v_1^(2) -v_2^(2))` Lift on the PLANE ` = L= Delta P xx A = (1)/(2)rho A (v_1^(2)-v_2^(2))` |
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