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अल. 112 f BeosB+12 5111 05 {3 then tan® = —-m‘ o= e ० by |
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Answer» 5cosx + 12sinx = 13, 5 + 12tanx = 13secx, Squarin both-sides,25 +144tanx^2 +120tanx = 169sec^2x=169(tan^2x +1),25(tanx)^2 - 120tanx + 144 = 0,(5tanx - 12)^2 = 0, tanx = 12/5 Hello i didn't understand |
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