1.

Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is:

Answer»

2000 Rs.



Let C.P. of each HORSE be Rs. X and C.P. of each cow be Rs. y. 

Then, 4x + 9y = 13400 -- (i)

And, 10% of 4x + 20% of 9y = 1880

2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (II)

Solving (i) and (ii), we get : x = 2000 and y = 600.

Cost price of each horse = Rs. 2000.



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