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Albert Is Travelling On His Cycle And Has Calculated To Reach Point A At 2 P.m. If He Travels At 10 Kmph, He Will Reach There At 12 Noon If He Travels At 15 Kmph. At What Speed Must He Travel To Reach A At 1 P.m.? |
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Answer» Let's Assume the distance travelled Albert = x km. Formula Used: Time = Distance/Speed => (3x - 2X)/30 = 2 hrs. => (3x - 2x) = 60 x = 60 km. Time taken to travel 60 km at 10 km/hr = 60/10 hrs = 6 hrs. Formula Used: Speed = Distance/Time So, Albert started 6 hours before 2 P.M. i.e @ 8 A.M. REQUIRED speed = 60/5 kmph. = 12 kmph. Let's Assume the distance travelled Albert = x km. Formula Used: Time = Distance/Speed so (x/10 - x/15) = 2 hrs => (3x - 2x)/30 = 2 hrs. => (3x - 2x) = 60 x = 60 km. Time taken to travel 60 km at 10 km/hr = 60/10 hrs = 6 hrs. Formula Used: Speed = Distance/Time So, Albert started 6 hours before 2 P.M. i.e @ 8 A.M. Required speed = 60/5 kmph. = 12 kmph. |
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