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Alcohol flows through two capillary tubes under a pressure lead. The diameter of the two tubes are in the ratio of 4:1 and the length are in the ratio of 1:4. Compare the rate of flow of alcohol through the two tubes. |
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Answer» <P> Solution :` ""(d_1)/(d_2) = (4)/(1)i.e.,(r_1)/( r_2)= (4)/( 1) ,(t_1)/( t_2)= (1)/(4)`Ratio of rate of flow `= ( Q_1)/( Q_2) = ? ` ` "" Q = (pi P R^(4))/( 8 eta l ) . ` Here ` eta ` and P are constant. `" So " ""Q PROP (r^(4))/(l) ` ` therefore ""(Q_1)/(Q_2)= (r_1^(4))/( l_1) xx (l_2)/( r_2^(4))xx (l_2)/( l_1)` ` therefore ""(Q_1)/(Q_2)= ((4)/(1)) ^(4)xx ((4)/( 1)) ` ` "" = 1024: 1` |
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