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Aldehydes and Ketones reacts with `NH_2OH` to form Aldoximes and Ketoximes respectively.Configuration of these can be determined by Beckmann rearrangement as that group migrates which is anti w.r.t-OH It is interesting to note that the migration of group is completely retentive and no loss of optical activity is seen. `CH_3CHO+NH_2OHoverset(Delta)toPoverset(H^(o+))toQoverset(Br_2//KOH)toR(CH_3NH_2)` (as only product) Following is correctA. Oxime P is syn form of geometrical isomersB. Oxime P is anti formC. Q is more basic than RD. Q is `H-undersetunderset(O)(||)C-NH-CH_3` |
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Answer» Correct Answer - B `CH_3-undersetunderset(O)(||)C-H+H_2N-OHtounderset((P))(CH_3-CH=N-OH("anti"))tounderset((Q))(CH_3-undersetunderset(O)(||)C-NH_2)overset("Heffmann Bromamide")toCH_3-NH_2` |
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