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`AlF_(3)` soluble in `HF` only in presence of KF. It is due to the formation ofA. `K_(3)[AlF_(3)H_(3)]`B. `K_(3)[AlF_(6)]`C. `AlH_(3)`D. `Kl[AlF_(3)H]` |
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Answer» Correct Answer - B Anhydrous `HF` is a covalent compound and is strongly H-bounded . Therefore , it does not give `F^(-)` ions and hence `AlF_(3)` does not compound contains `F^(-)` ions. Therefore, it combines with `AlF_(3)` to form soluble complex, `K_(3)[AlF_(6)]` `AlF_(3) + 3KF rarr K_(3)[AlF_(6)]` |
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