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All reactions are of 1st order . At time `t=t_1(t_1gt0)` `([B])/([C])=alpha`Therefore at time `t=t_2` (where `t_2get_1`) `([C])/([D])=beta`Which of the following is correct ?A. `alpha gt beta`B. `alpha=beta`C. `alphabeta=0.4`D. `alpha+beta=0.4`

Answer» Correct Answer - C
`[[B]]/[[C]]=(3k_1)/(8k_1)=3/8=alpha` (at any time)
`[[C]]/[[D]]=(8k_1)/(7.5k_2)=8/7.5=beta` (at any time)
`:. alphabeta=0.4`


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