Along the direction of propagation of one wave of frequency 120 Hz, phase difference between two particles separated by 1 m distance is 90^(@). Find velocity of this wave.

Along the direction of propagation of one wave of frequency 120 Hz, ph

1.	Along the direction of propagation of one wave of frequency 120 Hz, phase difference between two particles separated by 1 m distance is 90^(@). Find velocity of this wave.
Answer» `180 m//s` `240 m//s` `480 m//s` `720 m//s` SOLUTION :We KNOW that, `Delta phi = (2pi )/(lamda ) (Delta x )` `therefore Delta phi = (2pi f )/(V ) (Delta c ) ""(because v= f lamda )` `therefore (PI)/(2) = (2 pi xx 120)/(v) (1)` `therefore v = 480 m//s`