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`alpha`-chloropropanoic acid on treatment with alcoholic acid KOH followed by acidification gives :A. `CH_(3)-CH(OH)-CO OH`B. `CH_(2)=CH-CO OH`C. `HO-CH_(2)-CH_(2)-CO OH`D. `CH_(3)-CH_(2)-CO OH` |
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Answer» Correct Answer - 3 `CH_(3)CHClCO OH overset(alc KOH)toCH_(2)=CHCO OH` |
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