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Aluminium crystallizes in a cubic close-packed structre. Its metallic radius is `125 ppm` a. What is the length of the side of the unit cell? b. How many unit cell are there in `1.00 cm^(3)` of aluminium?A. `4.42xx10^(22)`B. `2.36xx10^(21`C. `2.26xx10^(22)`D. `3.6xx10^(18)` |
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Answer» Correct Answer - C For an fcc unit cell, `r=(a)/(2sqrt(2))` [Given, r = 125 pm] `a=2sqrt(2)xxr=2xx1.414xx125` `=353.5` pm `~~354` pm Volume of unit cell `=a^(3)=(353.5xx10^(-10)cm)^(3)` `=442xx10^(-25)cm^(3)` Number of unit cell `=(1.00cm^(3))/(442xx10^(-25)cm^(3))` `=2.26xx10^(22)` unit cells |
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