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Aluminium displaces hydrogen from acids, but copper does not. A galvanic cell prepared by combining `Cu//Cu^(2+)` and `Al//Al^(3+)` has an emf of 2.0V at 298. if the potential of copper electrode is +0.34V. That of Aluminium electrode isA. `-2.3V`B. `+2.34V`C. `-1.66V`D. `1.66V`. |
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Answer» Correct Answer - C Cell representation is `Al|Al^(2+)||C u^(2+)|Cu` `E_("cell")=E_(Cu^(2+))+_(//Cu)-E_(Al^(3))+_(//Al)` `2.0V== 0.34V-E_(Al^(3+)//Al)` `E_(Al^(3+)//Al)=0.34V-2.0V=-1.66V` |
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