Aluminium metal forms a cubic close-packed crystal structure. Its atomic radius is 125xx10^(-12)m. (a) Calculate the length of the side of the unit cell. (b) How many such unit cells are there in 1.00 m^3 of aluminium ?

Aluminium metal forms a cubic close-packed crystal structure. Its atom

1.	Aluminium metal forms a cubic close-packed crystal structure. Its atomic radius is 125xx10^(-12)m. (a) Calculate the length of the side of the unit cell. (b) How many such unit cells are there in 1.00 m^3 of aluminium ?
Answer» <html><body><p><br/></p>Solution :ccp=fcc. For fcc, `r=a/(2sqrt2)` or `a=2sqrt2r=2xx1.414xx125xx10^(-2) m =354xx10^(-12) m`=<a href="https://interviewquestions.tuteehub.com/tag/354-309041" style="font-weight:bold;" target="_blank" title="Click to know more about 354">354</a> <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a> <br/> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of one unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> =`(354xx10^(-12)m)^3=4.436xx10^(-29) m^3` <br/> `therefore` No. of unit cell in 1 `m^3=1/(4.436xx10^(-29))=2.25xx10^28`</body></html>