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Aluminium reduces manganese dioxide to manganese at high temperature. The amount of aluminium required to reduce one gram mole of manganese dioxide is -(A) 1/2 gram mole (B) 1 gram mole (C) 3/4 gram mole (D) 4/3 gram mole |
Answer» Correct option: (D) 4/3 gram mole Explanation: 4Al + 3MnO2 → 3Mn + 2Al2O3 To reduce 3 moles of MnO2 required moles of Al = 4 So, for one mole of MnO2 required moles of Al will be = 4/3 |
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