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Aluminum is exteracted from alumine `AI_(2)O_(3)` by electrolysis of a molten mixture of :A. `Al_(2)O_(3) + HF + NaAlF_(4)`B. `Al_(2)O_(3) + CaF_(2) + NaAlF_(4)`C. `Al_(2)O_(3) + Na_(3)AlF_(6) + CaF_(2)`D. `Al_(2)O_(3) + KF + Na_(3)AlF_(6)` |
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Answer» Correct Answer - C Alumina, `Al_(2)O_(3)` is a bad conductor of electricity and has very high melting point, so before subjecting to electrolysis, it is mixed with fluorspar `(CaF_(2))` and cryolite `(Na_(3)AlF_(6))`, which lower its melting point and make it more conducting. Mainly `CaF_(2)` and `Na_(3)AlF_(6)` are mixed with `Al_(2)O_(3)` for converting `Al_(2)O_(3)` in molten state. |
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