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Amanstartsbicyclingin themorningata temperaturearound25^(@)C hecheckedthe pressureof tirewhichis equalto be500 Kpa.Afternoonhe foundthat theabsolutepressurein thetyreis increasedto520 Kpa. Byassumingthe expansionof tyre is negligiblewhat isthetemperatureof typeat afternoon ? |
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Answer» Solution :For ideal gas equation of state `PV=nRT` `P_(1)=500kPa, T_(1)=25^(@)C=25+273=298K, P_(2)=520kPa, T_(2)=?` EXPANSION of tyre is negligible `(V_("CONSTANT"))` `(P_(V)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `therefore""T_(2)=((P_(2))/(P_(1)))T_(1)=(520)/(500)xx298=(154960)/(500)-=309.92K` `T_(2)=309.92-273, T_(2)=36.9^(@)C` |
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