Amita travels from her house at \(3 \frac{1}{2}\) km/h and reaches h

1.	Amita travels from her house at \(3 \frac{1}{2}\) km/h and reaches her school 6 minutes late. The next day she travels at \(4 \frac{1}{2}\)km/h and reaches her school 10 minutes early. What is the distance between her house and the school?1. 5.6 km2. 5.4 km3. 4.8 km4. 4.2 km
Answer» Correct Answer - Option 4 : 4.2 km Given: Speed 1 = 3.5 km/hr reaches 6 min late Speed 2 = 4.5 km/h reaches 10 min early. Formula used: Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference Calculation: Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference ⇒ Distance = [(3.5 × 4.5)/1] × 16/60 ⇒ 4.2 km ∴ The distance between her house and the school is 4.2 km. Mistakes Point: Convert all given data in same units i.e all-time in an hour or sec and distance in Km or meter according to requirements.

Amita travels from her house at \(3 \frac{1}{2}\) km/h and reaches her school 6 minutes late. The next day she travels at \(4 \frac{1}{2}\)km/h and reaches her school 10 minutes early. What is the distance between her house and the school?1. 5.6 km2. 5.4 km3. 4.8 km4. 4.2 km

Answer» Correct Answer - Option 4 : 4.2 km

Given:

Speed 1 = 3.5 km/hr reaches 6 min late

Speed 2 = 4.5 km/h reaches 10 min early.

Formula used:

Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference

Calculation:

Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference

⇒ Distance = [(3.5 × 4.5)/1] × 16/60

⇒ 4.2 km

∴ The distance between her house and the school is 4.2 km.

Mistakes Point:

Convert all given data in same units i.e all-time in an hour or sec and distance in Km or meter according to requirements.

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