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Ammonia gas at 76 cm Hg pressure was connected to a manometer. After sparking in the flask, ammonia is partially dissociated as follows : `2NH_(3) (g) hArr N_(2) (g) + 3H_(2) (g)` the level in the mercury column of the manometer was found to show the difference of 18 cm. What is the partial pressure of `H_(2) (g)` at equilibrium ?A. 18 cm HgB. 9 cm HgC. 27 cm HgD. 24 cm Hg |
Answer» Correct Answer - C `{:(,2NH_(3) (g),hArr,N_(2) (g) ,+ 3H_(2) (g)),(t_(0),76,,0," "0),(t_(eq),76 - 2x,,x," "3x):}` Total pressure after dissociation `= 76 - 2x + x + 3 x = 76 + 2x` `:.` Increase in pressure `= 2x = 18` `x = 9 cm` Partial pressure of `H_(2) = 3 x = 27 cm` |
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