1.

Ammonia is produced in accordance with this equation . `N_(2)(g) + 3H_(2)(g) rightarrow 2NH_(3)(g)` In a particular experiment, 0.25mol of `NH_(3)` is formed when 0.5 mol of `N_(2)` is reacted with 0.5 mol of `H_(2)`. What is the percent yield?A. 0.75B. 0.5C. 0.33D. 0.25

Answer» Correct Answer - A


Discussion

No Comment Found

Related InterviewSolutions