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Ammonia produced when 0.75 g of a substance was kjeldahlised neutralised `30 cm^(3)` of 0.25 `NH_(2)SO_(4)`. Calculate the persentage of nitrogen in the compound. |
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Answer» Mass of the organic substance =0.75 g Volume of `H_(2)SO_(4)` used up `=30 cm^(3)` Normality of sulphuric acid `= 0.25 N` `30 cm^(3)` of `H_(2)SO_(4)` of normality `0.25 N equiv 30 cm^(3)` of `NH_(3)` solution of normality 0.25 N But `1000 cm^(3)` of ammonia solution of normality 1 contain 14 g of nitrogen. `:.` Therefore, `30 cm^(3)` of 0.25 N ammonia solution will contain nitrogen `=14/1000xx30xx0.25` `:.` Percentage of nitrogen `=("Mass of nitrogen")/("Mass of substance")xx100=14/1000xx(30xx0.25)/(0.75)xx100=14.00`. |
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