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Among CaH_(2),BeH_(2),BaH_(2), the order of ionic character is- |
Answer» <html><body><p>`BeH_(2) lt CaH_(2) lt BaH_(2)`<br/>`CaH_(2) lt BeH_(2) lt BaH_(2)`<br/>`BeH_(2) lt HaH_(2) lt CaH_(2)`<br/>`BaH_(2) lt BeH_(2) lt CaH_(2)`.</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Down a group <a href="https://interviewquestions.tuteehub.com/tag/metallic-547634" style="font-weight:bold;" target="_blank" title="Click to know more about METALLIC">METALLIC</a> character <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a>. Thus <a href="https://interviewquestions.tuteehub.com/tag/ionic-1051191" style="font-weight:bold;" target="_blank" title="Click to know more about IONIC">IONIC</a> character of the metal hydride increases down the group. Hence least ionic compound is `BeH_(2)`.</body></html> | |