Among `KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+)`, unpaired electron is present inA. `NO_(2)^(+) and BaO_(2)`B. `KO_(2) and AlO_(2)^(-)`C. `KO_(2)` onlyD. `BaO_(2)` only

Among `KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+)`, unpaired electron

1.	Among `KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+)`, unpaired electron is present inA. `NO_(2)^(+) and BaO_(2)`B. `KO_(2) and AlO_(2)^(-)`C. `KO_(2)` onlyD. `BaO_(2)` only
Answer» Correct Answer - C Electrons present : `NO_(2)^(+) = 7 + 16 - 1 = 22 , BaO_(2) = 56 + 16 = 72 ` `AlO_(2)^(-) = 13 + 16 + 1 = 30 ` and `KO_(2) = 19 + 16 = 35` Thus , olny `KO_(2)` is odd electron species.

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Among `KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+)`, unpaired electron is present inA. `NO_(2)^(+) and BaO_(2)`B. `KO_(2) and AlO_(2)^(-)`C. `KO_(2)` onlyD. `BaO_(2)` only

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