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Among the elements with atomic number 9, 12 and 36, identify the element which is (a) highly electronegative, (b) an inert gas in nature, (c) highly electropositive in nature. Give reasons for your answer. |
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Answer» The electronic configurations of the elements are: Z (9): 1s2 2s2 2p5 Z (12): 1s2 2s2 2p6 3s2 Z (36): 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 (a) The element with Z= 9 (fluorine) is highly electronegative because it requires only one electron to have the configuration of nearest noble gas element and has also very small size. It is, in fact the most electronegative 4 (0) in the periodic table. (b) The element with Z = 36 (Krypton) is an inert gas element as it has ns2 p6 electronic configuration. (c) The element with Z = 12 (Magnesium) is highly electropositive in nature, since by losing two valence electrons, it will have the configuration of the noble gas neon. |
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