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Among the following species, identify the isostuctural pairs `NF_(3). NO_(3)^(-), BF_(3), H_(3)O, HN_(3)`A. `[NF_(3),NO_(3)^(-)]` and `[BF_(3),H_(3)O^(+)]`B. `[NF_(3)HN_(3)]` and `[NO_(3)^(-),BF_(3)]`C. `[NF_(3),H_(3)O^(+)]` and `[NO_(3)^(-),BF_(3)]`D. `[NF_(3),H_(3)O^(+)]` and `[HN_(3),BF_(3)]` |
Answer» Correct Answer - C Structure of a molecule can be ascertained by knowing the number of hybrid bonds in the molecule. Thus, In `NF_(3): H=1/2 (5+3-0+0)=4` Thus,N in `NF_(3)` is `sp^(3)` hybridized as 4 orbitals are involved in bonding. In `NO_(3)^(-): H=1/2(5+3-0+0)=3` Thus N in `NO_(3)^(-)` is `sp^(2)` hybridized as 3 orbitals are involved in bonding. in `BF_(3): H=1/2(3+3-0+0)=3` Thus B in `BF_(3)` is `sp^(2)` hybridized as again 3 orbitals are involved in bonding In `H_(3)O^(+): H=1/2(6+3-1+0)=4` Thus, O in `H_(2)O^(+)` is `sp^(3)` hybridized as 4 orbitals are involved in bonding. Thus, isostructural pairs are `[NF_(3),H_(3)O^(+)]` and `[NO_(3)^(-),BF_(3)]`. |
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