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The hybridization state of the central atom in `AlI_3` isA. `dsp^2`B. `sp^3`C. `sp^2`D. `sp` |
Answer» Correct Answer - C The ground-state electron configuration of `Al` is `[Ne]3s^2 3p^1`. Therefore, `Al` has three valence electrons. All the valence electrons are used to form bonds with three univalent I atoms: `I-underset(I)underset(|)Al-I` There are three bonded atoms and no lone pairs on the `Al` atom. Thus, the steric number of `Al` in `All_3` is `3+0=3`. We conclude that `Al` must be `sp^2`-hybridized. We predict that the `All_3` molecule is planar and all the `I-Al-I` bond angles are `120^@`. |
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