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Among the following , the number of compounds that can react with `PCl_5` to give `POCl_3` is. `O_2,CO_2,SO_2,H_2 O,H_2 SO_4,P_4 O_10`. |
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Answer» Correct Answer - `(4)` (i) `PCl_5 + O_2 rarr "No reaction"` (ii) `PCl_5 + CO_2 rarr "No reaction"` (iii) `6 PCl_5 + P_4 O_10 rarr 10 POCl_3` (iv) With limited amount of `H_2 O , PCl_5` gives `POCl_3` but with excess of water it does not give `POCl_3` but gives `H_3 PO_4`. (a) `PCl_5 + H_2 O ("limited") rarr POCl_3 + 2 HCl` (b) `PCl_5 + 4 H_2 O ("excess") rarr H_3 PO_4 + 5 HCl` (v) `PCl_5 + SO_2 rarr SOCl_2 ("Thionyl chloride") + POCl_3` (vi) `2 PCl_5 + H_2 SO_4 rarr underset (("Sulphuryl chloride")) (SO_2 Cl_2) + 2 POCl_3 + 2 HCl`. |
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