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Amongs V2O3, V2O4, V2O5, determine value of spin only magnetic moment for most basic oxide in BM (Bohr's megnatone): |
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Answer» Correct answer is (3) V2O3(V+3) is most basic oxide amongs the following Total no. of unpaired electrons in v+3 is n = 2 23V+3 = [Ar]3d2 → \(\sqrt{n(n+2)}\) or √8 = - 2.87 BM |
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