1.

Amongs V2O3, V2O4, V2O5, determine value of spin only magnetic moment for most basic oxide in BM (Bohr's megnatone):

Answer»

Correct answer is (3)

V2O3(V+3) is most basic oxide amongs the following

Total no. of unpaired electrons in v+3 is n = 2

23V+3 = [Ar]3d2

→ \(\sqrt{n(n+2)}\) or √8 = - 2.87 BM
 



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