Amongst `Ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `[NiCl_(4)]^(2-)`A. `[Ni(CO)_(4)] and [NiCl_(4)]^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is paramagneticB. `[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[Ni(CO)_(4)]` is paramagneticC. `[Ni(CO)_(4)] and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagneticD. `[Ni(CO)_(4)]` is diamagnetic and `[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are paramagnetic .

Amongst `Ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `[NiCl_(4)]^(2-)`A. `[Ni(CO

1.	Amongst `Ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `[NiCl_(4)]^(2-)`A. `[Ni(CO)_(4)] and [NiCl_(4)]^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is paramagneticB. `[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[Ni(CO)_(4)]` is paramagneticC. `[Ni(CO)_(4)] and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagneticD. `[Ni(CO)_(4)]` is diamagnetic and `[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are paramagnetic .
Answer» Correct Answer - C `[Ni(CO)_(4)] and [Ni(CN)_(4)]^(2-)` are both diamagnetic with no unpaired electrons `[NiCl_(4)]^(2-)` is paramagnetic with two unpaired electrons.