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Answer» 
 `H_2C=C=O` `H_2C=C=CH_2` SOLUTION :Along C-C single bond, numerous CONFORMATIONS are possible in 1,3-butadiene (a) . In some of these conformations , all the atoms may not lie in the same plane. In `CH_2=C=CH_2` (d), due to sp-hybridization of the central carbon, H-atoms on the terminal `CH_2` groups lie in perpendicular planes . However, in `CH_2=C=O` (c ), due to replacement of `CH_2` by O the two H-atoms on the `sp^2`-HYBRIDIZED `CH_2` group lie in the same plane in which the two carbon and the oxygen atoms lie. In compound (B), due to linear structure of H-C`-=`C- PORTION of the molecule , the three H-atoms on -HC =`CH_2` portion always lie in the same plane. Thus, options (b) and (c ) are correct.
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