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Amont the following the most reactive towards alcoholic KOH isA. `CH_(2)=CHBr`B. `CH_(3)COCH_(2)CH_(2)Br`C. `CH_(3)CH_(2)Br`D. `CH_(3)CH_(2)CH_(2)Br` |
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Answer» Correct Answer - B A Elimination of `Br^(-)` become easier due to the presence of carbonyl group. |
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