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ample 2 : If Z B and Z Q areacute angles such that sin B = sin Qthen prove that B = < QSolution : Let us consider two righttriangles ABC and PQR whereSo,B R |
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Answer» Let us suppose that ABQ is a right angle triangle such that triangle is right angled at B. Given sinB = sinQ Now sinB = AQ/BQ ...........1 sinQ = AB/BQ ...........2 Since sinB = sinQ then from equation 1 and 2, we get AQ/BQ = AB/BQ => AQ = AB Therefore triangle ABQ is isoscales triangle. So Angle B = Angle Q Hence proved. |
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