1.

ample 2 : If Z B and Z Q areacute angles such that sin B = sin Qthen prove that B = < QSolution : Let us consider two righttriangles ABC and PQR whereSo,B R

Answer»

Let us suppose that ABQ is a right angle triangle such that triangle is right angled at B.

Given

sinB = sinQ

Now

sinB = AQ/BQ ...........1

sinQ = AB/BQ ...........2

Since sinB = sinQ

then from equation 1 and 2, we get

AQ/BQ = AB/BQ

=> AQ = AB

Therefore triangle ABQ is isoscales triangle.

So Angle B = Angle Q

Hence proved.



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