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Ample 8.6 A car accelerates uniformly from 18 km h to 36 km h in 5 s.Calculate (i) the acceleration and (ii) thedistance covered by the car in that time. |
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Answer» Answer:GIVEN parametersTime taken (t) = 5 secInitial velocity (u) =18 km/hour u=18×100060×60s u = 5 m/sFinal velocity (v) =36km/hour v=36×100060×60s v =10 m/sWe need to calculate acceleration and distance traveledWe know thatacceleration a = (v – u)/tSubstituting the given VALUES in the above equation we get,a = (10 – 5)/5A =5/5a = 1 m/s2We know that distance travelled is calculated by the formulaDistance travelled S = u t + (1/2) a × t2Substituting the given values in the above equation we get,S = 5 × 5 + (1/2) × 1 × 52S = 25 + (1/2) × 25S = 25 + 12.5S = 37.5 mHenceacceleration a =1 m/s2Distance travelled S =37.5 m |
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