Amplitude of a SHO is sqrt(5) cm. At what displacement fromthe mean position the ratio of kinetic energy to potential energy is 4?

Amplitude of a SHO is sqrt(5) cm. At what displacement fromthe mean po

1.	Amplitude of a SHO is sqrt(5) cm. At what displacement fromthe mean position the ratio of kinetic energy to potential energy is 4?
Answer» SOLUTION :`implies ("KINETIC energy")/("Potential energy")= 4` Kinetic energy = 4 potential energy `therefore (1)/(2)k(A^(2)-x^(2))= 4(1)/(2)KX^(2)` `therefore A^(2)- x^(2) = 5x^(2)` `therefore A^(2)= 5x^(2)` `therefore x = pm (A)/(sqrt(5))= pm (sqrt(5))/(sqrt(5))= 1 CM`.