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An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire isA. 0.14NB. 0.24NC. 0.34ND. 0.44N |
Answer» Correct Answer - B `F=Il B sin theta` Here, `theta=90^(@),I=10A,` `l= 8cm = 8xx10^(-2)m, B=0.3T` `therefore" "F=10xx8xx10^(-2)xx0.3xxsin 90^(@)=0.24N` |
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