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An AC current is given by `I=I_(0)+I_(1)` sin wt then its rms value will beA. `sqrt(I_(0)^(2)+0.5I_(1)^(2))`B. `sqrt(I_(0)^(2)+0.5I_(0)^(2))`C. `0`D. `I_(0)//sqrt(2)` |
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Answer» Correct Answer - A `I_(rms)=sqrt(1/Tint_(0)^(T)(I_(0)+I_(1) sin omegat)^(2)dt)` `sqrt(1/T int_(0)^(T)I_(0)^(2)dt+int_(0)^(T)I_(1)^(2) sin^(2) omegatdt+int_(0)^(T)(2I_(0)I_(1))/T sin 2omegatdt)` `=sqrt(I_(0)^(2)+(I_(1)^(2)//2))=sqrt(I_(0)^(2)+0.5I_(1)^(2))` |
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